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Algebra / Systems of Equations

Systems of Equations Word Problems

Most real problems that lead to a system have the same shape: two unknown quantities and two facts that connect them. Once you can turn each fact into an equation, the solving part is just substitution or elimination.

Practice Problems
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MPhil in Mathematics, Founder of Mathovia
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You know how to solve a system. The hard part of most homework and test questions is building it in the first place. Systems of equations word problems all follow the same recipe: there are two things you don’t know, and the problem tells you two facts about them. Each fact becomes an equation, and the pair of equations is the system. This lesson walks through that recipe, then applies it to the seven kinds of problem you’re most likely to meet. If you’ve solved these with a single variable before, as in the word problems lesson, you’ll find two variables make the setup much more direct.

Two unknowns and two facts give a system of two equations a1 x + b1 y = c1 and a2 x + b2 y = c2
Two unknowns plus two facts make a system

How to Set Up a System From a Word Problem

  1. Name the unknowns. Write down what each variable stands for, with units: ” = number of cookies sold”.
  2. Find two independent facts. Usually one is about a count or size (how many, how long) and the other about a value (how much money, how much acid, how far).
  3. Write one equation per fact.
  4. Solve with substitution or elimination.
  5. Answer the question asked, in words and units, and check against the original wording.
Two sentences from a bake-sale problem turned into equations: 120 items were sold becomes c + b = 120, and cookies at $1.50 and brownies at $2 totalling $205 becomes 1.5c + 2b = 205
The count fact and the money fact each become one equation

Common Types of Systems Word Problems

TypeEquation 1 (count or size)Equation 2 (value or rate)
tickets or items
coins or bills
investments
mixtures
wind or current
break-even
geometrya perimeter or angle totala relationship between the sides

Notice the pattern in the first four rows: the first equation counts, and the second equation weights each count by a price, value, rate or concentration.

Example 1: Items Sold

A bake sale sold items, cookies at and brownies at , and took in . How many of each were sold?

Step 1 — unknowns: cookies, brownies.

Step 2 — equations:

Step 3 — substitute :

Step 4 — back-substitute: .

Step 5 — check: ✓.

The sale sold 70 cookies and 50 brownies.

Example 2: Coins and Bills

A cash drawer holds bills, all and , worth in total. How many of each bill are there?

Step 1 — unknowns: five-dollar bills, ten-dollar bills.

Step 2 — equations: count ; value .

Step 3 — eliminate: multiply the count equation by and subtract it from the value equation:

Step 4 — back-substitute: .

There are 16 five-dollar bills and 14 ten-dollar bills. Check: ✓.

Example 3: Investments at Two Rates

Maria invests , part at and the rest at simple annual interest. After one year she has earned in interest. How much did she invest at each rate?

Step 1 — unknowns: dollars at , dollars at .

Step 2 — equations:

Step 3 — substitute :

Step 4 — back-substitute: .

She invested at 4% and at 6%. Check: ✓. Write rates as decimals, , or the interest equation will be off by a factor of .

Example 4: Mixing Two Solutions

A chemist needs liters of a acid solution. She has a solution and a solution. How much of each should she mix?

Step 1 — unknowns: liters of the solution, liters of the solution.

Step 2 — equations. The volumes add up, and so does the amount of pure acid. The final mixture holds liters of acid:

Step 3 — substitute :

Step 4 — back-substitute: .

She should mix 10 L of the 20% solution with 20 L of the 50% solution.

Three beakers: 10 liters at 20 percent holding 2 liters of acid, plus 20 liters at 50 percent holding 10 liters of acid, equals 30 liters at 40 percent holding 12 liters of acid
Both the liquid and the acid add up, which gives the two equations

The answer makes sense: is closer to than to , so the mix needs more of the stronger solution. There’s a one-variable approach to this kind of question in the mixture problems lesson.

Example 5: Wind and Current

A plane flies miles with a tailwind in hours. The return trip, against the same wind, takes hours. Find the plane’s speed in still air and the speed of the wind.

Step 1 — unknowns: = plane’s speed in still air, = wind speed, both in mph.

Step 2 — equations. With the wind the speeds add; against it they subtract. Distance is speed times time:

Step 3 — simplify each equation:

Step 4 — add them to eliminate :

The plane flies at 270 mph in still air, and the wind blows at 30 mph.

Two lanes: with the wind, the plane's speed p and wind w point the same way, giving 4(p + w) = 1200 and ground speed 300 mph; against the wind they point opposite ways, giving 5(p − w) = 1200 and ground speed 240 mph
With the wind the speeds add; against it they subtract

Boats in a river current work exactly the same way: downstream speed is , upstream speed is .

Example 6: Break-Even Point

A small business makes phone cases. Its fixed costs are , each case costs to make, and each sells for . How many cases must it sell to break even?

Step 1 — unknowns: = cases sold, = dollars.

Step 2 — equations: cost ; revenue .

Step 3 — break-even means cost = revenue:

Step 4 — the dollar value: .

The business breaks even at 100 cases, when both cost and revenue are . Below that it runs at a loss; above it, every extra case earns of profit.

Cost line C = 500 + 3x and revenue line R = 8x crossing at the break-even point (100, 800), with the loss region shaded before it and the profit region after it
Left of the break-even point is a loss; right of it is a profit

Example 7: Geometry

A rectangle’s length is cm more than twice its width, and its perimeter is cm. Find its dimensions.

Step 1 — unknowns: = length, = width, in cm.

Step 2 — equations: and .

Step 3 — substitute:

Step 4 — back-substitute: .

The rectangle is 15 cm by 6 cm. Check: ✓.

Choosing the Fastest Method

What the system looks likeFastest method
one equation is a simple total, substitution
one equation already reads substitution, or set the two expressions equal
two equations like and elimination by adding
decimals or percentagesmultiply by or first to clear them

Common Mistakes to Avoid

  • Not defining the variables. “Let = number of adult tickets” stops you from mixing up which value is which at the end.
  • Mixing counts and values. counts items; totals dollars. Don’t set a count equal to a dollar amount.
  • Using percentages as whole numbers. is , not .
  • Adding the wind to both legs. With the wind is ; against it is .
  • Stopping at one variable. If the question asks for both quantities, find both, and answer in words.

Practice Problems

Work each one before opening the answer.

Problem 1. Two numbers add up to , and their difference is . Find the numbers.

Show answer

Step 1 — equations: and .

Step 2 — add them:

Answer: and

Problem 2. Movie tickets cost for adults and for children. A group bought tickets for . How many of each did they buy?

Show answer

Step 1 — equations: and .

Step 2 — substitute :

Step 3 — back-substitute: .

Answer: adult and child tickets

Problem 3. A boat travels km downstream in hours and returns upstream in hours. Find the boat’s speed in still water and the speed of the current.

Show answer

Step 1 — equations: and , so and .

Step 2 — add them:

Answer: boat km/h, current km/h

Problem 4. is split between an account paying and one paying . The total yearly interest is . How much is in each account?

Show answer

Step 1 — equations: and .

Step 2 — substitute :

Step 3 — back-substitute: .

Answer: at and at

Problem 5. Candy worth per pound is mixed with candy worth per pound to make pounds worth per pound. How many pounds of each are used?

Show answer

Step 1 — equations: weight ; value .

Step 2 — substitute :

Step 3 — back-substitute: .

Answer: lb of the candy and lb of the candy

Problem 6. Phone plan A costs a month plus per minute. Plan B costs a month plus per minute. At how many minutes do they cost the same, and what is that cost?

Show answer

Step 1 — equations: and .

Step 2 — set them equal:

Step 3 — the cost: .

Answer: minutes, at

That completes the toolkit for this chapter: what a system is, three ways to solve one, systems with three variables and with matrices, nonlinear systems, systems of inequalities, and now the skill of building a system from a real situation. Whenever a problem gives you two unknowns and two facts, you know what to do. Once your equations are set up, the system of equations calculator will solve them with every step shown, so you can check your work.

Frequently Asked Questions

How do you set up a system of equations from a word problem?+

Name the two unknown quantities with variables. Find two separate facts in the problem, usually one about a total count or size and one about a total value, cost or rate, and write one equation for each. Then solve with substitution or elimination and answer in the units of the question.

How do you know which method to use to solve a word problem system?+

If one equation is a simple total like , substitution is usually quickest: solve it for one variable and substitute. If both equations have messy coefficients, elimination is usually cleaner. Both give the same answer.

What are the most common types of systems of equations word problems?+

Ticket or item sales, coins and bills, investments at two interest rates, mixtures of two solutions, boats and planes with a current or wind, break-even problems comparing cost and revenue, and geometry problems with perimeter and side relationships.

Why do word problems need two equations?+

Each unknown needs its own piece of information. With two unknowns and only one equation, there are infinitely many pairs that fit. A second independent fact narrows it down to exactly one pair.

How do you check the answer to a systems word problem?+

Put the values back into the original wording, not just your equations. If your equations were set up wrong, the values can satisfy them and still fail the story. Check every fact the problem states, and that the answer makes sense, such as no negative tickets.

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