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Algebra / Common Graphs

Parabolas: How to Graph a Quadratic Function

Every quadratic function graphs as a parabola — a single U-shaped curve with one turning point and a mirror line down the middle. This lesson covers the two forms you will meet, what each number in them controls, how to find the vertex and both kinds of intercept, and a five-point method that gets an accurate sketch on paper in under a minute.

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Drop a ball, aim a satellite dish, or trace the cable on a suspension bridge and you get the same curve. A parabola is the graph of a quadratic — any function whose highest power of is 2 — and it is the second shape most algebra courses teach after the straight line.

Vertex form of a quadratic function
Vertex form of a quadratic function

What Makes a Curve a Parabola

A parabola is the graph of

That matters. If were zero the term would vanish and you would be left with — a straight line, not a curve.

Two features define every parabola:

  • One turning point, the vertex, where the curve stops falling and starts rising (or the reverse).
  • A vertical mirror line through that vertex, the axis of symmetry. Fold the page along it and the two halves match exactly.
The parabola y = x squared with its vertex at the origin, a dashed vertical axis of symmetry, and pairs of points at equal heights marked on either side
Points at the same height sit at equal distances from the axis.

That symmetry is not decoration — it is the single most useful property when sketching, because it means every point you plot on one side gives you a second point free.

What the Coefficient a Controls

The number in front of does two jobs at once.

Its sign sets the direction. Positive opens the curve upward, so the vertex is a minimum. Negative opens it downward, so the vertex is a maximum.

Its size sets the width. A large squeezes the curve narrow; a small spreads it wide.

Four parabolas on one grid comparing a equals 3, 1 and 0.3 opening upward and a equals negative 1 opening downward
Bigger |a| is narrower; a negative a flips the curve over.
Value of DirectionShape against
upwardnarrower
upwardthe reference curve
upwardwider
downwardmirrored vertically

A quick sanity check: at one unit right of the vertex, the curve has risen exactly . At two units right it has risen . That “1, 4, 9 times ” pattern is worth memorising — it is how you place points without a calculator.

The Two Forms

Standard form is . Its gift is the -intercept: setting leaves , so you can read it off with no work at all.

Vertex form is

and its gift is the vertex, sitting right there as . As with the equation of a circle, the bracket subtracts the coordinate, so you negate what you see: means .

The parabola y equals x squared shown faded, with y equals (x minus 3) squared minus 4 drawn beside it and arrows showing a shift right 3 and down 4
Vertex form reads directly as a shift of y = x².

Read that way, vertex form is just picked up and moved: right by , up by , and stretched by . Converting standard form into vertex form is exactly the completing the square procedure used on circles.

Finding the Intercepts

The -intercept is . One point, free.

The -intercepts are wherever , so they are the solutions of — which is to say, they are the roots of the quadratic equation. Solve by factoring when you can and by the quadratic formula when you cannot.

How many there are is decided before you solve anything, by the discriminant :

Discriminant-interceptsWhat the graph does
twocrosses the axis twice
onejust touches, vertex on the axis
nonefloats entirely above or below
The parabola y equals x squared minus 6x plus 5 with its vertex at (3, negative 4), axis of symmetry x equals 3, x-intercepts at (1, 0) and (5, 0), and y-intercept at (0, 5) all labelled
One parabola with everything a question can ask for, labelled.

A parabola with no -intercepts is not an error. sits a full unit above the axis and never reaches it, which is a perfectly good answer.

The Five-Point Method

Tables of values waste effort, because symmetry means half the rows are predictable. This is faster and more accurate:

  1. Find the vertex. Either read it from vertex form, or use and substitute back — the method covered in vertex and axis of symmetry.
  2. Draw the axis of symmetry as a dashed vertical line through it.
  3. Plot two points on one side. One and two units across is usually enough.
  4. Mirror them to the other side at the same heights.
  5. Join the five points with a smooth curve — never straight segments, and never a sharp corner at the vertex.
The five-point sketching method on y equals x squared minus 6x plus 5, showing the vertex, two plotted points and their two mirrored partners numbered in order
Plot one side, mirror it, and the sketch is done.

Worked Example A: Sketch From Vertex Form

Sketch .

The vertex is and , so it opens upward and is narrower than .

One unit right of the vertex the curve has risen , giving . Two units right it has risen , giving . Mirroring across gives and .

Five points, and the -intercepts came out of the working for free.

Worked Example B: Sketch From Standard Form

Sketch .

The -intercept is .

The axis of symmetry is , and , so the vertex is .

For the -intercepts, , giving and .

Plot , , , , and the mirror of the -intercept at .

Worked Example C: A Downward Parabola

Describe the graph of .

is negative, so it opens downward and the vertex is a maximum. The bracket means , so the vertex is .

Because the curve is wider than . It has a maximum value of 6, reached at .

Worked Example D: Counting the Intercepts First

How many -intercepts does have?

Negative, so none. Since the parabola opens upward, so it sits entirely above the -axis.

Worked Example E: Building the Equation From a Graph

A parabola has vertex and passes through . Find its equation.

Start in vertex form: . Substituting the known point,

So . One extra point is always enough to pin down once you know the vertex.

Common Mistakes to Avoid

  • Getting the vertex signs backwards. means , not 3.
  • Assuming every parabola crosses the -axis. Plenty do not, and “no real roots” is a complete answer.
  • Drawing a sharp point at the vertex. A parabola turns smoothly; only absolute-value graphs have a corner.
  • Reading as the width alone. Its sign carries the direction too.
  • Plotting points blindly on both sides. Symmetry halves the work.
  • Forgetting when the curve is stretched. At one unit from the vertex the rise is , not 1.
  • Confusing the axis of symmetry with the vertex. The axis is a line, ; the vertex is a point.

Where Parabolas Lead Next

  • Maximum and minimum problems. The vertex answers every “largest area” and “greatest height” question — see vertex and axis of symmetry.
  • Conic sections. A parabola is the conic you get by slicing a cone parallel to its side; circles, ellipses and hyperbolas are the rest of the family.
  • Projectile motion. Under constant gravity, height against time is quadratic.
  • Quadratic inequalities. Knowing where the curve sits above or below the axis solves them by inspection.
  • Reflector design. A parabolic dish focuses every incoming parallel ray onto one point, which is why satellite dishes and headlight reflectors have this cross-section.

Practice Problems

Work each one before opening the answer.

Problem 1. Which way does open, and is its vertex a maximum or a minimum?

Show answer

, so it opens downward and the vertex is a maximum.

Problem 2. State the vertex of .

Show answer

.

Problem 3. State the vertex of .

Show answer

. The plus inside the bracket means .

Problem 4. What is the -intercept of ?

Show answer

— the constant term.

Problem 5. Find the -intercepts of .

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gives and , so and .

Problem 6. How many -intercepts does have?

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, so exactly one. The curve touches the axis at its vertex, .

Problem 7. How many -intercepts does have?

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, so none.

Problem 8. Is narrower or wider than ?

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Narrower, because .

Problem 9. Write in standard form.

Show answer

.

Problem 10. A parabola has vertex and passes through . Find its equation.

Show answer

, so and . The equation is .

Problem 11. A parabola has vertex and passes through . Find its equation in vertex form.

Show answer

, so and . The equation is .

Problem 12. Sketch using five points.

Show answer

Axis ; vertex . Intercepts from at and . The -intercept is , mirrored to .

Quick Reference

TaskMethod
Standard form
Vertex form
Direction up, down
Widthlarger is narrower
-intercept, the constant term
-interceptssolve
Number of -interceptssign of
Axis of symmetry
Rise from the vertex at 1 across, at 2 across
Fast sketchvertex, two points, mirror both

Parabolas are the curve half of graphing equations, and their intercepts are the roots you find in quadratic equations. The next lesson, vertex and axis of symmetry, goes deeper on locating that turning point. To drill the algebra underneath, try the quadratic equations practice problems. More Algebra lessons are available.

Frequently Asked Questions

What is a parabola?+

It is the graph of any quadratic function with . It has exactly one turning point, called the vertex, and it is symmetric about a vertical line through that vertex.

Which way does a parabola open?+

The sign of decides it. If the parabola opens upward and the vertex is the lowest point; if it opens downward and the vertex is the highest point.

What does the value of a do to a parabola?+

Its sign sets the direction and its size sets the width. A larger makes a narrower curve, a smaller a wider one. Compared with , the graph of is three times as steep at every horizontal offset.

How do you find the y-intercept of a parabola?+

Set . In standard form that leaves , so the constant term is the -intercept and no work is needed.

How many x-intercepts can a parabola have?+

Two, one, or none. The discriminant decides: positive gives two, zero gives one (the vertex sits on the axis), and negative gives none, because the curve never crosses.

What is the difference between standard form and vertex form?+

Standard form hands you the -intercept directly. Vertex form hands you the vertex directly. Completing the square converts standard form into vertex form.

Do you need a table of values to graph a parabola?+

No, and a plain table is usually the slowest route. Find the vertex, plot two points on one side of it, then mirror them across the axis of symmetry — five points is enough for an accurate sketch.

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