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Algebra / Polynomial Functions

The Remainder and Factor Theorem

These two theorems turn division into a yes-or-no test. The remainder theorem says the leftover from dividing by x − a is exactly P(a); the factor theorem says that when that leftover is zero, x − a is a factor.

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Dividing a polynomial just to see whether it divides evenly is a lot of work for a yes-or-no answer. The remainder theorem and the factor theorem remove that work: instead of carrying out the division, you substitute one number. Together they are the bridge between dividing polynomials and finding their zeros, and almost everything in the rest of this chapter leans on them.

The Remainder and Factor Theorem — key formula
Key formula

The Remainder Theorem

When a polynomial is divided by , the remainder is .

That is the whole statement. The remainder of a division by a linear factor is never something you have to compute by dividing — it is just the polynomial evaluated at one point. It holds for polynomials of any degree, from a quadratic to a degree-twelve monster; the divisor being linear is the only condition.

Why it is true takes a single line. Start from the division algorithm, with a constant remainder because the divisor is linear:

Now substitute :

The factor is built to vanish at , which wipes out the quotient term no matter what is. Whatever survives is the remainder.

The Factor Theorem

is a factor of if and only if .

This is the remainder theorem with . If the remainder is zero, the division was exact, so — a factorisation. And if is a factor, then substituting gives zero.

The “if and only if” matters. It means the statement is usable in both directions:

  • Given a candidate factor, test it by substituting. One evaluation, no division.
  • Given a zero, you immediately own a factor — which is how a known root gets peeled off a high-degree polynomial.

Four Ways of Saying the Same Thing

For a polynomial and a number , these four statements are completely interchangeable. Recognising them as one idea in four costumes is most of what this chapter asks of you.

StatementLanguage it belongs to
evaluating
is a factor of factoring
is a zero (or root) of solving
the graph crosses or touches the -axis at graphing
Four equivalent statements: P of a equals zero, x minus a is a factor, a is a zero, and the graph meets the x-axis at a
One fact, four vocabularies — each is a route into the others

An exam question that gives you any one of these is silently handing you the other three.

Getting a on the Right Side of the Sign

The theorems are stated for . A divisor written any other way has to be reshaped first.

DivisorRewritten as Test this value

The sign flips. A divisor of tests , because is the number that makes equal zero. This is the same trap as the box in synthetic division, and it catches people just as often here.

Worked Example: Testing a Factor

Is a factor of ?

Step 1 — the divisor is already in form, so . Evaluate:

Step 2 — work it out:

Step 3 — apply the factor theorem. The value is zero, so is a factor.

This is the same polynomial divided in the long division lesson, where the full division gave quotient and remainder . The factor theorem reached the same conclusion in one substitution instead of a full tableau — though note it tells you that is a factor without telling you the other factor. When you need the quotient too, divide.

Worked Example: Using the Remainder Theorem for a Value

Find the remainder when is divided by .

Step 1 — rewrite the divisor and read off :

Step 2 — evaluate the polynomial there:

Step 3 — compute carefully, minding the powers of a negative:

The remainder is . Because it is not zero, is not a factor.

Both the long division and the synthetic division of this same polynomial ended on — three different methods, one answer, and this one took a single line.

Worked Example: Peeling Off a Known Zero

You are told that is a zero of . Factor it completely.

Step 1 — apply the factor theorem in reverse. A zero at means is a factor.

Step 2 — divide it out with synthetic division, root , coefficients :

Step 3 — read the bottom row . The remainder is as promised, and the quotient is:

Step 4 — factor the quadratic, which is now small enough to do by inspection:

Step 5 — assemble:

One known zero collapsed a cubic into a quadratic, and the quadratic finished the job. That is the standard pattern for factoring anything above degree two.

Common Mistakes to Avoid

  • Testing for the divisor . The value that matters is the one making the divisor zero, which is . Rewrite every divisor as before substituting.
  • Mishandling powers of a negative. but . Brackets around the negative number, every time.
  • Concluding a factorisation from one test. tells you is a factor, not the whole story. You still have to divide to find what else is there.
  • Assuming the theorems apply to any divisor. Both are stated for linear . There is no substitution test for divisibility by — that needs actual division.
  • Reading a non-zero remainder as failure. A remainder of is not a dead end; it is the exact value of , which is often what the question wanted in the first place.

Practice Problems

Work each before opening the answer.

Problem 1. Use the factor theorem to decide whether is a factor of .

Show answer

Step 1 — here . Evaluate:

Step 2 — simplify:

Answer: yes — , so is a factor.

Problem 2. Find the remainder when is divided by .

Show answer

Step 1 — , so compute :

Step 2 — simplify:

Answer: the remainder is . Since it is not zero, is not a factor.

Problem 3. Is a factor of ?

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Step 1 — rewrite as , so :

Step 2 — evaluate each term, watching the signs:

Answer: yes — is a factor.

Problem 4. For what value of is a factor of ?

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Step 1 — the factor theorem requires . Substitute:

Step 2 — set it to zero and solve:

Step 3 — check by substituting back into :

Answer:

Problem 5. Given that is a zero of , factor it completely.

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Step 1 — a zero at means is a factor. Divide synthetically with root and coefficients :

Step 2 — the quotient is ; factor it:

Answer: , with zeros at , and

Problem 6. A synthetic division of by ends with the number in the bottom-right position. State three things you now know.

Show answer

Step 1 — the bottom-right entry is the remainder, so .

Step 2 — by the remainder theorem, that remainder is , so .

Step 3 — by the factor theorem, a zero value means is a factor. And a zero of the polynomial is an -intercept of its graph.

Answer: ; is a factor of ; the graph of meets the -axis at . All four equivalent statements at once, from one number.

The factor theorem tells you what to do with a zero once you have one — but not where to look for it in the first place. The next lesson supplies that: the rational root theorem narrows an infinite search down to a short list of candidates, each of which you can test with a single substitution or one row of synthetic division.

Frequently Asked Questions

What is the factor theorem?+

It states that is a factor of if and only if . The "if and only if" runs both ways: a zero at guarantees the factor, and the factor guarantees the zero. It is the remainder theorem with the remainder set to zero.

What is the difference between the remainder theorem and the factor theorem?+

The remainder theorem is the general statement — dividing by leaves remainder , whatever that value is. The factor theorem is the special case where that remainder happens to be , which is exactly when divides evenly.

Why does the remainder equal P(a)?+

Write the division as . Substituting makes the first term , so . The whole proof is one substitution — the factor is built to vanish at .

Does the factor theorem work for divisors like x + 3?+

Yes — rewrite it in the shape first. is , so and you test . Testing instead is the most common way this goes wrong.

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