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Calculus / Calculus 1 · Limits

Types of Discontinuity

A discontinuity is a place where a function breaks, but not all breaks are alike. A hole can be patched with a single point, a jump can't, and an infinite break comes with a vertical asymptote. The one-sided limits tell you exactly which kind you're looking at.

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The continuity lesson gave a three-part test: defined, the limit exists, and the two are equal. When the test fails, the function has a discontinuity at , and the way it fails tells you which type. There are three main types of discontinuity, removable, jump and infinite, and one less common kind, oscillating. Telling them apart takes nothing more than the one-sided limits.

Removable: the limit exists but is not equal to f(a), or f(a) is undefined. Jump: the left and right limits are finite but different. Infinite: a one-sided limit is plus or minus infinity
The three main types in terms of limits
Four graphs: a removable discontinuity with a hole on the curve and a separate dot above it; a jump discontinuity where the left piece ends at an open circle and the right piece starts higher with a filled dot; an infinite discontinuity with a vertical asymptote; and an oscillating discontinuity where sin of 1 over x wiggles faster and faster
Removable, jump, infinite and oscillating

Removable Discontinuity

A removable discontinuity happens when exists, but is undefined or equal to something else. On a graph it’s a hole in an otherwise smooth curve, sometimes with a stray dot above or below it. It’s the only kind you can fix: redefine as the limit and the function becomes continuous.

Example. at . Factor: for . The limit is 5, but is undefined, so there’s a removable discontinuity at . Defining fills the hole.

In rational functions, removable discontinuities come from factors that cancel between the top and bottom. The rational functions lesson calls them holes.

Jump Discontinuity

A jump discontinuity happens when both one-sided limits are finite numbers but they’re different. The graph jumps from one height to another, and the size of the jump is the difference between the two limits.

Example. for and for . From the left, ; from the right, . The jump has size 3. Because the two sides disagree, no value of could make the function continuous, so a jump is non-removable.

Jumps are typical of piecewise functions and step functions such as the floor function, which jumps by 1 at every integer. They also model real prices: a parking fee that rises by a fixed amount at the start of each hour jumps at every hour mark.

Infinite Discontinuity

An infinite discontinuity happens when at least one one-sided limit is or . The graph has a vertical asymptote there, as covered in infinite limits.

Example. at : the left side falls to and the right side rises to , so there’s an infinite discontinuity. has one too, even though both sides go up.

Oscillating Discontinuity

Occasionally a function neither settles nor blows up. swings between and 1 faster and faster as , so neither one-sided limit exists. This is called an oscillating (or essential) discontinuity. It’s rare in practice, but it’s the reason the classification has more than three cases.

How to Find and Classify Points of Discontinuity

Flowchart: find both one-sided limits at x = a. Both finite and equal, with f(a) missing or different, means removable. Both finite but different means jump. At least one side infinite means infinite. A side that never settles means oscillating
Classify by the one-sided limits
  1. List the candidates. Zeros of every denominator, edges of the domain (from roots and logs), and the points where a piecewise function changes formula. Everywhere else, familiar functions are continuous.
  2. Compute the one-sided limits at each candidate, and if it exists.
  3. Classify with the flowchart: equal finite limits mean removable (unless they match , in which case it’s continuous after all), different finite limits mean a jump, and an infinite side means an infinite discontinuity.

Worked Example: Two Types in One Function

Find and classify the discontinuities of .

Factor: . The denominator is zero at and , so those are the candidates.

Graph of (x² − 4)/(x² − x − 2): a vertical asymptote at x = −1, a horizontal asymptote at y = 1, and an open circle at (2, 4/3)
A hole at x = 2 and an asymptote at x = −1
  • At : the factor cancels, leaving . The limit exists but doesn’t, so this is a removable discontinuity, a hole at .
  • At : the simplified form gives , so the one-sided limits are infinite. This is an infinite discontinuity, with the vertical asymptote .

This is the standard pattern for rational functions: factors that cancel leave holes, and factors that stay in the denominator leave asymptotes.

Removable vs Non-Removable

The practical difference is whether the limit exists. If it does, the discontinuity is removable and a single redefinition fixes it. If it doesn’t, because the sides disagree (a jump), blow up (infinite) or never settle (oscillating), the discontinuity is non-removable. When a question asks for “the value that makes continuous”, it’s always a removable discontinuity, and the answer is the limit.

Common Mistakes to Avoid

  • Calling every zero of the denominator an asymptote. Cancel first; a cancelled factor gives a hole.
  • Judging a jump from one side. You need both one-sided limits to see the jump.
  • Thinking a dot fixes a jump. A filled dot at doesn’t help if the two sides approach different heights.
  • Forgetting the switch points of a piecewise function. They’re the most common place for a jump.

Practice Problems

Work each one before opening the answer.

Problem 1. Classify the discontinuity of at .

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It simplifies to , so the limit is 8 but is undefined.

Answer: removable

Problem 2. Classify the discontinuity of at .

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: the one-sided limits are infinite.

Answer: infinite

Problem 3. For when and when , classify the discontinuity at .

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Left limit 2, right limit 4: finite but different.

Answer: jump (of size 2)

Problem 4. What value of removes the discontinuity of at ?

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, which approaches .

Answer:

Problem 5. Find and classify every discontinuity of .

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for . At the limit is ; at it’s .

Answer: removable at , infinite at

Next, the intermediate value theorem: why a continuous function can’t skip any values, and how to use that to prove an equation has a solution.

Frequently Asked Questions

What are the 3 types of discontinuity?+

Removable discontinuities (a hole, where the limit exists but doesn't match the function's value), jump discontinuities (the left and right limits are finite but different), and infinite discontinuities (at least one side goes to , giving a vertical asymptote). Some courses add a fourth, oscillating, for functions like near 0.

What is a removable discontinuity?+

It's a point where exists, but is either undefined or a different number. It's called removable because redefining as the limit removes the break. In rational functions it shows up as a hole, from a factor that cancels.

How do you find points of discontinuity?+

List the candidates: zeros of a denominator, endpoints of a domain, and the points where a piecewise function switches formulas. At each one, compute the one-sided limits and to see whether the function is continuous there and, if not, which kind of discontinuity it has.

What is the difference between a removable and a non-removable discontinuity?+

At a removable discontinuity the two-sided limit exists, so changing one point fixes it. Jump and infinite discontinuities are non-removable: the limit doesn't exist, so no single value of can make the function continuous.

Is a vertical asymptote a discontinuity?+

Yes. A vertical asymptote at means at least one one-sided limit is infinite there, which is an infinite discontinuity.

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