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Math Practice Generator

Complex Number Arithmetic Generator: Free Practice for All Four Operations

Practice all four complex number operations — adding, subtracting, multiplying, and dividing — plus powers of i and conjugate products, with instant feedback across three difficulty levels.

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Mathovia Team
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Complex Number Arithmetic Generator

The Complex Number Arithmetic lesson covers all four operations in full; this generator drills them with heavier repetition on powers of \(i\) and conjugate products — the two ideas that reappear most often once you move past the basics.

How the difficulty levels work

DifficultyWhat it drillsExample
EasyAdd or subtract two complex numbersReal or imaginary part of \((4+3i)+(7+8i)\)
MediumA power of \(i\), or multiplying two complex numbers\(i^{18} = -1\)
HardDividing, a bigger power of \(i\), or a conjugate product\((5+2i)(5-2i) = 29\)

Easy adds or subtracts two complex numbers, asking for either the real or the imaginary part of the result.

Medium alternates between simplifying a power of \(i\) (always landing on \(1\) or \(-1\)) and multiplying two complex numbers with FOIL.

Hard rotates through three shapes: dividing two complex numbers using the conjugate, a much larger power of \(i\), and a genuine conjugate product, always fully real.

Using the generator

Pick a difficulty and a question count, and a fresh set appears instantly. Whole-number answers go in as-is; division problems accept a fraction or its decimal equivalent.

  • Check Answers scores the set and flags exactly which problems need another look
  • Show Answers reveals every solution, useful for reviewing a paper attempt
  • Print Worksheet outputs a clean page for offline practice or classroom handouts

The rules this generator drills

RuleStatement
Add or subtractCombine real parts and imaginary parts separately
MultiplyFOIL, then replace \(i^{2}\) with \(-1\)
DivideMultiply top and bottom by the denominator’s conjugate
Powers of \(i\)Cycle every four: \(i, -1, -i, 1\)

See the Complex Number Arithmetic lesson for the full derivation of each rule and worked examples for every operation.

Common mistakes to watch for

Forgetting to replace \(i^{2}\) with \(-1\) after multiplying. A term like \(6i^{2}\) is not a finished answer; it has to become \(-6\).

Losing a sign when \(i^{2}\) turns a subtraction into an addition. \(9-4i^{2}\) becomes \(9+4=13\), not \(9-4=5\).

Miscounting the four-step cycle of \(i\). Divide the exponent by \(4\) and use the remainder — a miscounted cycle is the most common error in the power-of-\(i\) problems.

Writing a conjugate with the wrong sign. The conjugate of \(2-3i\) is \(2+3i\) — only the imaginary part’s sign flips.

Where to go next

For the same conjugate technique applied to a radical instead of a complex number, see the Rationalizing Denominators Generator. For every rule’s full derivation, see the Complex Number Arithmetic lesson.

Frequently Asked Questions

Why does every problem ask for just the real or imaginary part?+

A full complex number like 7+i is two values in one, which can't be automatically checked as a single number. Asking for one part at a time still requires the complete calculation — the answer is just one checkable value instead of a pair.

How is this different from the Complex Number Generator?+

Both cover the same four operations, but this generator leans more heavily on powers of i, at every difficulty, and always uses a genuine conjugate product at Hard — more repetition on the two ideas the Complex Number Arithmetic lesson spends the most time on.

Why do powers of i only ever use even exponents in the answer key?+

An odd power of i is itself imaginary (i, −i, and so on), which isn't a single real number the checker can validate the usual way — every power-of-i problem here uses an even exponent, which always lands on a real result: 1 or −1.

Why is a conjugate product always a whole number?+

A complex number times its own conjugate, (a+bi)(a−bi), always simplifies to a²+b² — the imaginary parts cancel completely by construction, which is exactly why the conjugate trick clears i from a denominator.

How do I divide by a complex number?+

Multiply the numerator and denominator by the denominator's conjugate — the same complex number with the sign of its imaginary part flipped — which always turns the denominator into a real number.

Is there a limit on how many problems I can generate?+

No. Sets are generated on demand and are unlimited and free, with no account required.

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