Mathovia

Math Practice Generator

Complex Number Generator: Free Practice Adding, Multiplying & Dividing Complex Numbers

Practice adding, multiplying, and dividing complex numbers, plus simplifying powers of i, with instant feedback across three difficulty levels.

M
Written by
Mathovia Team
Editorial Team

Complex Number Generator

Adding, multiplying, and dividing complex numbers are covered in full in the Complex Numbers lesson; this generator is where that skill turns into speed. Since a complex answer like \(5-2i\) isn’t a single checkable number, every problem asks for one coordinate of it — the real part, the imaginary part, or (for a conjugate product, which is always fully real) the whole result.

How the difficulty levels work

DifficultyWhat it drillsExample
EasyAdd or subtract, find one part\((3+4i)+(2-5i) \to \text{real} = 5\)
MediumMultiply with FOIL, find one part\((2+3i)(1+4i) \to \text{real} = -10\)
HardConjugate products, powers of i, or division\((4+i)(4-i) = 17\)

Easy adds or subtracts two complex numbers and asks for either the real or the imaginary part of the result.

Medium multiplies two complex numbers with FOIL, replacing \(i^{2}\) with \(-1\) along the way, then asks for one part of the result.

Hard rotates between three shapes: a conjugate product (always a real number, \(a^{2}+b^{2}\)), a power of \(i\) (always an even exponent here, so the answer is always \(1\) or \(-1\)), and dividing two complex numbers using the conjugate, asking for one part of the (often fractional) result.

Using the generator

Pick a difficulty and a question count, and a fresh set appears instantly. Most answers are whole numbers; the Hard-tier division problems sometimes produce a fraction, entered the same way as any other fraction answer on this site.

  • Check Answers scores the set and flags exactly which problems need another look
  • Show Answers reveals every solution, useful for reviewing a paper attempt
  • Print Worksheet outputs a clean page for offline practice or classroom handouts

The rules this generator drills

RuleStatement
Definition\(i^{2} = -1\)
Addition\((a+bi)+(c+di) = (a+c)+(b+d)i\)
Multiplication\((a+bi)(c+di) = (ac-bd)+(ad+bc)i\)
Conjugate Product\((a+bi)(a-bi) = a^{2}+b^{2}\)

See the Complex Numbers lesson for the full derivation of each rule, plus the powers-of-i cycle and dividing by conjugate in detail.

Common mistakes to watch for

Treating \(i^{2}\) as \(+1\) instead of \(-1\). This single substitution drives almost every problem here — get it backward and the sign of the whole answer flips.

Reporting the imaginary part with an \(i\) attached. The imaginary part of \(3-14i\) is \(-14\), a plain number — not \(-14i\).

Multiplying straight across instead of using FOIL. \((a+bi)(c+di)\) needs all four cross products, exactly like multiplying two binomials.

Losing track of the power-of-i remainder. A remainder of \(2\) always means \(-1\); double-check the division before answering.

Where to go next

Once these feel automatic, the Radical Generator practices the exact same conjugate technique used here, aimed at radical denominators instead of imaginary ones. For the full reasoning behind every rule drilled here, see the Complex Numbers lesson.

Frequently Asked Questions

Why does every problem ask for the real part or imaginary part instead of the full answer?+

A complex number like 3-14i isn't a single number the way 7 or 3/4 is, so it can't be automatically checked the same way. Asking for just the real part or just the imaginary part still requires computing the full result correctly — it's checked one coordinate at a time instead of all at once.

What does "imaginary part" actually mean as a number?+

For a complex number a+bi, the imaginary part is just b — a real number, the coefficient of i, not b times i. The imaginary part of 3-14i is -14, not -14i.

Why do the Hard-tier conjugate problems ask for the whole answer instead of one part?+

Because (a+bi)(a-bi) always equals a²+b², a real number with no imaginary part at all — there's nothing to split into two coordinates, so the whole result is already a single checkable number.

How do I simplify i to a large power, like i to the 40th?+

Divide the exponent by 4 and use the remainder: 0 gives 1, 1 gives i, 2 gives -1, 3 gives -i. Every power-of-i problem here uses an even exponent, so the answer is always 1 or -1.

Do I need Radicals before this generator?+

Rational Exponents and Radicals aren't required to practice the arithmetic here, but the Complex Numbers lesson explains i as an extension of the same radical ideas — worth reviewing if the conjugate technique feels unfamiliar.

Is there a limit on how many problems I can generate?+

No. Sets are generated on demand and are unlimited and free, with no account required.

More practice generators