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Math Practice Generator

Radical Generator: Free Practice for Simplifying, Multiplying & Rationalizing Radicals

Practice evaluating and multiplying radical expressions, including conjugate products and decimal approximations of non-perfect roots, with instant feedback across three difficulty levels.

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Mathovia Team
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Radical Generator

Simplifying, multiplying, and rationalizing radicals are procedural skills — the Radicals lesson covers the reasoning behind each one, and this generator is where that reasoning turns into speed, with unlimited fresh problems and instant right/wrong feedback.

How the difficulty levels work

DifficultyWhat it drillsExample
EasyEvaluate a perfect square or cube root\(\sqrt{81} = 9\)
MediumMultiply two radicals to a perfect square\(\sqrt{2} \cdot \sqrt{8} = 4\)
HardConjugates, larger products, decimal approximations\((4+\sqrt{12})(4-\sqrt{12}) = 4\)

Easy evaluates a single perfect square or perfect cube root, so the answer is always a clean whole number.

Medium multiplies two radicals whose product lands on a perfect square, applying the Product Rule for Radicals from the lesson: \(\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}\), then simplifying.

Hard rotates between three shapes: a conjugate product like \((a+\sqrt{b})(a-\sqrt{b})\), which always eliminates the radical entirely; a larger radical product; and a genuine decimal approximation of a non-perfect root, entered to two decimal places.

Using the generator

Pick a difficulty and a question count, and a fresh set appears instantly. Whole-number answers go in as-is; the decimal-approximation problems at Hard accept a small margin around the rounded value.

  • Check Answers scores the set and flags exactly which problems need another look
  • Show Answers reveals every solution, useful for reviewing a paper attempt
  • Print Worksheet outputs a clean page for offline practice or classroom handouts

The rules this generator drills

RuleStatement
Product Rule for Radicals\(\sqrt[n]{ab} = \sqrt[n]{a} \cdot \sqrt[n]{b}\)
Power of a Radical\(\left(\sqrt[n]{a}\right)^{n} = a\)
Conjugate Product\((a+\sqrt{b})(a-\sqrt{b}) = a^{2}-b\)

See the Radicals lesson for the full derivation of each rule, plus simplifying, combining, and rationalizing techniques this generator doesn’t cover directly.

Common mistakes to watch for

Forgetting to multiply the coefficients too. \((4\sqrt{7})(3\sqrt{7})\) isn’t \(\sqrt{7}\) times something small — the \(4\) and \(3\) multiply together first, giving \(12 \cdot 7 = 84\).

Getting a conjugate’s sign backward. The conjugate of \(a-\sqrt{b}\) is \(a+\sqrt{b}\) — only the middle sign flips.

Rounding a decimal approximation too aggressively. \(\sqrt{54} \approx 7.35\), not \(7.3\) or \(7\) — keep two decimal places for the Hard-tier approximation problems.

Assuming a non-perfect square has no real answer. Every radicand here is nonnegative; a decimal approximation always exists even when the exact value is irrational.

Where to go next

Once these feel automatic, the Rational Exponent Generator practices the exact same ideas written as fractional exponents instead of radical signs. For the full reasoning behind every rule drilled here, see the Radicals lesson.

Frequently Asked Questions

Why is every answer a single number instead of a simplified radical?+

This generator drills the arithmetic behind radicals — evaluating roots, multiplying them, and clearing them with a conjugate — using problems that are deliberately built so the final answer is always one checkable number. Simplifying a radical into "6√2" form is exactly what the Radicals lesson's Example 1 walks through with full solutions.

What does the approximately-equal sign mean on some Hard problems?+

It marks a genuine, non-perfect root, like \(\sqrt{54}\), whose exact value is irrational. Enter your answer rounded to two decimal places; the checker accepts a small margin either way.

Why do conjugate problems always come out as whole numbers?+

\((a+\sqrt{b})(a-\sqrt{b})\) is a difference of squares, \(a^{2}-b\), and both \(a^{2}\) and \(b\) are whole numbers by construction — the radical cancels out completely every time, which is exactly why conjugates are the standard tool for rationalizing a binomial denominator.

How do I type a decimal approximation answer?+

Just the number, like 7.35. You don't need to type the approximately-equal sign or round to more than two decimal places.

Do I need to know Integer Exponents or Rational Exponents first?+

Rational Exponents is the more direct prerequisite, since a radical is just a fractional exponent written differently. If any rule here feels unfamiliar, the Radicals lesson derives everything from scratch.

Is there a limit on how many problems I can generate?+

No. Sets are generated on demand and are unlimited and free, with no account required.

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