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Math Practice

Work Rate Practice Problems

Twelve hand-built work-rate problems with full worked solutions. Each uses the fact that a worker finishing a job in a hours completes 1/a of it per hour, and combined rates add up to one whole job.

Written by
MPhil in Mathematics, Founder of Mathovia
Published

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Work Rate Practice Problems

The Work Problems lesson explains why rates add and works through every case; this set is 12 problems to practice on, each with a full solution.

How to use this set

For each problem, write each worker’s rate as , multiply by the time worked, set the sum of the parts to , and solve. Put the time in the answer box and press Check Answers. The placeholder tells you which unit the problem wants, and fractions such as 15/7 are accepted alongside decimals.

Common mistakes to watch for

Adding the times instead of the rates. “5 hours and 20 hours, so 25 together” is the classic wrong answer.

Forgetting to invert. The combined rate is a sum; the combined time is its reciprocal.

Adding a drain’s term instead of subtracting it.

Accepting a together-time larger than the fastest solo time.

Where to go next

The same chart and reciprocal idea drive the Distance, Rate, and Time Practice Problems. Clearing the denominators is the Linear Equations with Fractions Practice Problems skill. For every case, see the Work Problems lesson.

Frequently Asked Questions

What is the main idea behind a work-rate problem?+

Rates of work add. A worker who does a job in hours has rate ; working with a second worker of rate , the combined rate is , and the time together is the reciprocal of that.

Why is the whole job the number 1?+

One finished job is 100% of the work, which is . Each worker's contribution is the fraction of that job they complete, and the fractions sum to when the job is done.

What is the two-worker formula?+

If they take and hours alone, together they take where , which gives .

How do I handle a worker who leaves early?+

Give that worker a shorter time expression, like instead of . Each term is still (that worker's time) over (that worker's solo time).

How does a drain fit in?+

A drain does negative work, so its term is subtracted: . This only has a positive solution when the fill is faster than the drain.

What is a quick sanity check?+

For a 'working together' problem, the combined time must be shorter than the faster worker's solo time. A larger answer means a reciprocal or sign error.

Can I answer with a fraction instead of a decimal?+

Yes. Times that do not come out evenly can be entered either way, so 15/7 and 2.14 are both marked correct. Watch the unit the problem is using: some of these are stated in hours and some in minutes, and the placeholder says which.

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