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Equations Reducible to Quadratic Form Practice Problems

Twelve hand-built equations in quadratic form with full worked solutions. Each shows the choice of u, the quadratic in u, its solutions, and the back-substitution that recovers every value of the original variable.

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MPhil in Mathematics, Founder of Mathovia
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Equations Reducible to Quadratic Form Practice Problems

The Equations Reducible to Quadratic Form lesson covers three substitution patterns; this set is 12 equations to practice on, each fully solved.

How to use this set

Identify the repeated expression, substitute , solve the quadratic in , then back-substitute and solve for the original variable — checking for extraneous roots where an even root is involved. Type every real solution into the box, separated by commas, and press Check Answers. The ± shorthand works too, so ±1, ±2 is read as the four values it stands for.

Common mistakes to watch for

Stopping at the -solutions without back-substituting.

Forgetting the when .

Discarding a negative without thought — with it gives complex ; with it is rejected.

Skipping the extraneous check on equations with .

Where to go next

The quadratic in is solved by factoring or the Quadratic Formula Practice Problems. Equations with a single isolated radical are the Equations with Radicals Practice Problems. For the substitution patterns, see the Equations Reducible to Quadratic Form lesson.

Frequently Asked Questions

What does it mean for an equation to be in quadratic form?+

It can be written as for some expression . The clue is that one term's variable part is the square of another's — is the square of , so is quadratic in .

How do I choose u?+

Let be the expression whose square appears in the highest-degree term. For , take ; for , take ; for , take .

Do I always get four solutions from a quartic?+

Not always. Each -value gives up to two -values from . A negative gives complex ; a repeated gives fewer distinct .

When do I check for extraneous solutions?+

Whenever the substitution or back-substitution uses an even root — like , which cannot be negative. Reject any -value that violates that.

What is the last step?+

Back-substitute: replace with the original expression and solve for the original variable. Solving for is never the final answer.

How do I enter four solutions at once?+

List them separated by commas in any order. The ± shorthand saves typing: ±1, ±2 is read as the four values -2, -1, 1, 2. Where a substitution produces roots that are not real, give only the real ones unless the problem asks otherwise.

More practice problems